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Ultrafilter! Waffle!

Below are the 10 most recent journal entries recorded in the " Ultrafilter! May 7th, 2011. Let K/k be the splitting field of an irreducible quintic over k. Show that K cannot contain a root of any irreducible cubic over k. March 31st, 2011. Compute sum {k=0} n (-1) k binom{n}{k}/(k 1). March 26th, 2011. Find a commutative ring R, a multiplicative subset S subset R, and finitely generated R-modules M and N such that the natural map S {-1}Hom(M,N) to Hom(S {-1}M,S {-1}N) is not an isomorphism. Done the obv...

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Ultrafilter! Waffle! | ultrawaffle.livejournal.com Reviews
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Below are the 10 most recent journal entries recorded in the Ultrafilter! May 7th, 2011. Let K/k be the splitting field of an irreducible quintic over k. Show that K cannot contain a root of any irreducible cubic over k. March 31st, 2011. Compute sum {k=0} n (-1) k binom{n}{k}/(k 1). March 26th, 2011. Find a commutative ring R, a multiplicative subset S subset R, and finitely generated R-modules M and N such that the natural map S {-1}Hom(M,N) to Hom(S {-1}M,S {-1}N) is not an isomorphism. Done the obv...
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Ultrafilter! Waffle! | ultrawaffle.livejournal.com Reviews

https://ultrawaffle.livejournal.com

Below are the 10 most recent journal entries recorded in the " Ultrafilter! May 7th, 2011. Let K/k be the splitting field of an irreducible quintic over k. Show that K cannot contain a root of any irreducible cubic over k. March 31st, 2011. Compute sum {k=0} n (-1) k binom{n}{k}/(k 1). March 26th, 2011. Find a commutative ring R, a multiplicative subset S subset R, and finitely generated R-modules M and N such that the natural map S {-1}Hom(M,N) to Hom(S {-1}M,S {-1}N) is not an isomorphism. Done the obv...

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1

On cleverness in LARPs - Ultrafilter! Waffle!

http://ultrawaffle.livejournal.com/202204.html

On cleverness in LARPs - Ultrafilter! February 23rd, 2011. On cleverness in LARPs. Done the obvious calculation and thought about it (with the outcome and your thoughts about it mentioned in the character sheet), that seems to me to be a nontrivial statement about your character. Anyways, the moral of the story is that character sheets need to be very thorough, because an omission of an idea in a character sheet is just as significant as an inclusion. February 23rd, 2011 03:26 pm (UTC).

2

FLMPotD - Ultrafilter! Waffle!

http://ultrawaffle.livejournal.com/200793.html

February 2nd, 2011. Show that x 4-16x 2 4 is reducible mod p for every prime p. Stolen from a comment by. On a post on. S facebook. Yay stalking! PS: Actually, my argument should work for anything of the form x 4 bx 2 c 2 for b and c integers and p odd.). February 3rd, 2011 11:08 am (UTC). I think it has to be c 4 2bx 2 c 2? Using the proof with Galois Theory that I'm not allowed to use. Rawr.). Powered by LiveJournal.com.

3

FLMPotD - Ultrafilter! Waffle!

http://ultrawaffle.livejournal.com/201388.html

February 4th, 2011. Prove Picard's big theorem (in a neighborhood of an essential singularity, a holomorphic function's image misses at most one point of C) using only the fact that the holomorphic universal cover of C-{0,1} is the unit disk, elementary complex analysis, and covering space theory. Powered by LiveJournal.com.

4

FLMPotD - Ultrafilter! Waffle!

http://ultrawaffle.livejournal.com/201049.html

February 3rd, 2011. Show that the ring Q[sin,cos] (say as a subring of the ring of functions on R) is spanned by the functions sin nx and cos nx as n varies. There's an unenlightening trivial solution using obscure trig identities, and then a more interesting conceptual solution.). February 3rd, 2011 06:50 am (UTC). Doesn't that follow trivially from C[sin x, cos x]=C[e x, e (-x)]? February 3rd, 2011 07:01 am (UTC). February 3rd, 2011 07:36 pm (UTC). February 3rd, 2011 08:05 pm (UTC).

5

March 12th, 2007 - Ultrafilter! Waffle!

http://ultrawaffle.livejournal.com/2007/03/12

March 12th, 2007 - Ultrafilter! March 12th, 2007. March 12th, 2007. So Muffin has a new boyfriend, and my dad has many crazy questions about/for him. As he said to Muffin, "If there are any questions you're too embarrassed to ask, I'm not." So he made a list of questions to ask him, and I joined in on the fun a little too. But then there were some unintended consequences. Here is an excerpt:. 12 Does he like math? 13 Does he like blueberries? 14a Does his sister like math? Powered by LiveJournal.com.

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Guessing the result of infinitely many coin tosses | Antimeta

https://antimeta.wordpress.com/2008/09/26/guessing-the-result-of-infinitely-many-coin-tosses

A general distrust of strong metaphysical claims in mathematics and philosophy. Guessing the result of infinitely many coin tosses. I’ve stolen the title of a very interesting post. Check out his post. To see the description of the strategy, or work it out yourself, before going on. Anyway, I managed to figure this out, only because it’s formally identical to a game with colored hats. He begins his discussion with a discussion of a very nice paper. Laquo; The Role of Existence Proofs. 8230;] A couple of ...

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Ultrafilter! Waffle!

Below are the 10 most recent journal entries recorded in the " Ultrafilter! May 7th, 2011. Let K/k be the splitting field of an irreducible quintic over k. Show that K cannot contain a root of any irreducible cubic over k. March 31st, 2011. Compute sum {k=0} n (-1) k binom{n}{k}/(k 1). March 26th, 2011. Find a commutative ring R, a multiplicative subset S subset R, and finitely generated R-modules M and N such that the natural map S {-1}Hom(M,N) to Hom(S {-1}M,S {-1}N) is not an isomorphism. Done the obv...

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